\(\begin{array}{l}
1)\\
a)\\
nC{O_2} = \frac{{0,88}}{{44}} = 0,02\,mol =  > nC = 0,02\,mol\\
n{H_2}O = \frac{{0,36}}{{18}} = 0,02mol =  > nH = 0,04\,mol\\
mO = 0,6 - mC - mH = 0,32g\\
 =  > A:C,H,O\\
b)\\
nO = \frac{{0,32}}{{16}} = 0,02\,mol\\
nC:nH:nO = 0,02:0,04:0,02 = 1:2:1\\
 =  > CTDGN:C{H_2}O\\
30n = 60 =  > n = 2\\
 =  > CTPT:{C_2}{H_4}{O_2}\\
2)\\
a)\\
nC{O_2} = \frac{{19,8}}{{44}} = 0,45\,mol =  > nC = 0,45\,mol\\
n{H_2}O = \frac{{10,8}}{{18}} = 0,6\,mol =  > nH = 1,2mol\\
mO = 9 - 0,45 \times 12 - 1,2 = 2,4g\\
 =  > A:C,H,O\\
b)\\
nO = \frac{{2,4}}{{16}} = 0,15\\
nC:nH:nO = 0,45:1,2:0,15 = 3:8:1\\
 =  > CTDGN:{C_3}{H_8}O\\
60n = 60 =  > n = 1\\
 =  > CTPT:{C_3}{H_8}O\\
c)\\
C{H_3} - C{H_2} - C{H_2} - OH\\
C{H_3} - CH(OH) - C{H_3}\\
C{H_3} - C{H_2} - O - C{H_3}
\end{array}\)