Đáp án + Giải thích các bước giải:

Dãy `1:`

\(Al \to Al_2O_3 \to AlCl_3 \to Al(OH)_3 \to Al_2(SO_4)_3\\(1) \quad 4Al + 3O_2 \overset{t^o}\to 2Al_2O_3\\(2) \quad Al_2O_3 + 6HCl \to 2AlCl_3 + 3H_2O\\(3) \quad AlCl_3 + 3NaOH \to Al(OH)_3 + 3NaCl\\(4) \quad 2Al(OH)_3 + 3H_2SO_4 \to Al_2(SO_4)_3 + 6H_2O\)

Dãy `2:`

\(Al_2(SO_4)_3 \to AlCl_3 \to Al(OH)_3 \to Al_2O_3 \to Al\\(1) \quad Al_2(SO_4)_3 + 3BaCl_2 \to 2AlCl_3 + 3BaSO_4\\(2) \quad AlCl_3 + 3NaOH \to Al(OH)_3 + 3NaCl\\(3) \quad 2Al(OH)_3 \overset{t^o}\to Al_2O_3 + 3H_2O\\(4) \quad 2Al_2O_3 \xrightarrow{{ đpnc}} 4Al + 3O_2\)

Đáp án `+` Giải thích các bước giải `!`

`@` Dãy `1:` `Al to Al_2O_3 to AlCl_3 to Al(OH)_3 to Al_2(SO_4)_3`

PTHH:

`4Al+3O_2` `overset(t^o)to` `2Al_2O_3`

`Al_2O_3+6HCl` $\longrightarrow$ `2AlCl_3+3H_2O`

`AlCl_3+3NaOH` $\longrightarrow$ `Al(OH)_3+3NaCl`

`2Al(OH)_3+3H_2SO_4` $\longrightarrow$ `Al_2(SO_4)_3+6H_2O`

`@` Dãy `2:` `Al_2O_3 to Al to AlCl_3 to  Al(OH)_3 to Al_2(SO_4)_3`

PTHH:

`2Al_2O_3` `overset(t^o)to` `4Al+3O_2`

`2Al+3Cl_2` $\longrightarrow$ `2AlCl_3`

`AlCl_3+3NaOH` $\longrightarrow$ `Al(OH)_3+3NaCl`

`2Al(OH)_3+3H_2SO_4` $\longrightarrow$ `Al_2(SO_4)_3+6H_2O`