Em tham khảo nha:

\(\begin{array}{l}
1)\\
b)\\
{V_{CO}} = 0,25 \times 22,4 = 5,6l\\
{V_{{H_2}}} = 2,5 \times 22,4 = 56l\\
{V_{{N_2}}} = 2 \times 22m4 = 44,8l\\
c)\\
{n_{{O_2}}} = \dfrac{{0,32}}{{32}} = 0,01\,mol\\
{n_{C{l_2}}} = \dfrac{{1,42}}{{71}} = 0,02\,mol\\
{n_{S{O_2}}} = \dfrac{{0,64}}{{64}} = 0,01\,mol\\
{n_{hh}} = 0,01 + 0,02 + 0,01 = 0,04\,mol\\
{V_{hh}} = 0,04 \times 22,4 = 0,896l\\
2)\\
a)\\
{n_{Fe}} = \dfrac{{28}}{{56}} = 0,5\,mol\\
{A_{Fe}} = 0,5 \times 6 \times {10^{23}} = 3 \times {10^{23}}\\
{n_{Cu}} = \dfrac{{6,4}}{{64}} = 0,1\,mol\\
{A_{Cu}} = 0,1 \times 6 \times {10^{23}} = 6 \times {10^{22}}\\
b)\\
{V_{{H_2}}} = 2 \times 22,4 = 44,8l\\
{m_{{H_2}}} = 2 \times 2 = 4g\\
{V_{{O_2}}} = 1,5 \times 22,4 = 33,6l\\
{m_{{O_2}}} = 1,5 \times 32 = 48g\\
{V_{CO}} = 1,15 \times 22,4 = 25,76l\\
{m_{CO}} = 1,15 \times 28 = 32,2g\\
{V_{C{H_4}}} = 1,15 \times 22,4 = 25,76l\\
{m_{C{H_4}}} = 1,15 \times 16 = 18,4g
\end{array}\)