Đáp án:

 Vậy \(\left[ \begin{array}{l}\widehat{M_{1}}=80°\\\widehat{M_{2}}=100°\\\widehat{M_{3}}=80°\\\widehat{M_{4}}=100°\end{array} \right.\)

 Vậy \(\left[ \begin{array}{l}\widehat{N_{1}}=80°\\\widehat{N_{2}}=100°\\\widehat{N_{3}}=80°\\\widehat{N_{4}}=100°\end{array} \right.\)

Giải thích các bước giải:

 Do `hat{P_{3}}`=`hat{Q_{1}}`(So le trong)

⇒ $a//b$ (Tiên đề ơ clit)

Do $a//b$ (cmt)

Ta có: `hat{M_{2}}`=`hat{M_{4}}`=100°(đối đỉnh)

Ta có: `hat{M_{2}}`+`hat{M_{3}}`=180°(kề bù)

⇒ `hat{M_{3}}`=180°-100°=80°

Ta có :`hat{M_{3}}`=`hat{M_{1}}`=80°(đối đỉnh)

Ta có: `hat{M_{3}}`=`hat{N_{3}}`=80°(đồng vị)

Ta có: `hat{M_{2}}`=`hat{N_{2}}`=100°(đồng vị)

Ta có: `hat{N_{2}}`=`hat{N_{4}}`=100°(đối đỉnh)

Ta có: `hat{N_{3}}`=`hat{N_{1}}`=80°(đối đỉnh)

Vậy \(\left[ \begin{array}{l}\widehat{M_{1}}=80°\\\widehat{M_{2}}=100°\\\widehat{M_{3}}=80°\\\widehat{M_{4}}=100°\end{array} \right.\)

 Vậy \(\left[ \begin{array}{l}\widehat{N_{1}}=80°\\\widehat{N_{2}}=100°\\\widehat{N_{3}}=80°\\\widehat{N_{4}}=100°\end{array} \right.\)