Đáp án + Giải thích các bước giải:

1, `|(-7)/16| + ((-3)/4)^2 - sqrt{25}`

`= 7/16 + 9/16 - 5`

`= 16/16 - 5`

`= 1 - 5 = -4`

2, `(2020/2021)^0 - |(-7)/18| + |1/18|`

Quy ước : `a^0 = 1`  `(a \ne 0)`

`= 1 - 7/18 + 1/18`

`= 18/18 - 7/18 + 1/18`

`= 12/18 = (12:6)/(18:6) = 2/3`

3, `28 : (-7/3)^2 - 5/14 * sqrt{64}`

`= 28 : 49/9 - 5/14 * 8`

`= 28 xx 9/49 - 40/14`

`= (2^2*3^2*7)/(7^2) - 20/7`

`= (2^2*3^2)/7 - 20/7`

`= 36/7 - 20/7`

`= 16/7`

11, `(2^{15}*9^3)/(6^7*4^4)`

`= (2^{15}*9^3)/(2^7*3^7*2^8)`

`= (2^8*3^6)/(3^7*2^8)`

`= (3^6)/(3^7)`

`= 1/(3^{7-6})`

`= 1/3`

`1. |(-7)/16|+((-3)/4)^2-\sqrt{25}`

`=7/16+9/16-5`

`=16/16-5`

`=1-5`

`=-4`

`2. (2020/2021)^0-|(-7)/18|+|1/18|`

`=1-7/18+1/18`

`=1-6/18`

`=1-1/3`

`=3/3-1/3`

`=2/3`

`3. 28:(-7/3)^2-5/(14).\sqrt{64}`

`=28:49/9-5/(14).8`

`=28.(9)/49-20/7`

`=36/7-20/7`

`=16/7`

`11. (2^(15).9^3)/(6^(7).4^4)`

`=(2^(15).(3^2)^3)/((3.2)^(7).(2^2)^4)`

`=(2^(15).3^6)/(3^(7).2^(7).2^8)`

`=(2^(15).3^6)/(3^(7).2^15)`

`=1/3`