1)

$CuSO_4+2NaOH\to Cu(OH)_2+Na_2SO_4$

$Cu(OH)_2\xrightarrow{{t^o}} CuO+H_2O$

$CuO+H_2\xrightarrow{{t^o}} Cu+H_2O$

2)

$Na_2O+H_2O\to 2NaOH$

$NaOH+HCl\to NaCl+H_2O$

$NaCl+AgNO_3\to NaNO_3+AgCl$

3)

$MgCl_2+2AgNO_3\to Mg(NO_3)_2+2AgCl$

$Mg(NO_3)_2+2KOH\to Mg(OH)_2+2KNO_3$

$Mg(OH)_2\xrightarrow{{t^o}} MgO+H_2O$

$MgO+H_2SO_4\to MgSO_4+H_2O$

4)

$Na_2CO_3+Ba(OH)_2\to BaCO_3+2NaOH$

$2NaOH+CO_2\to Na_2CO_3+H_2O$

$Na_2CO_3+2HCl\to 2NaCl+CO_2+H_2O$

$2NaCl+2H_2O\xrightarrow{{đpmn}} 2NaOH+H_2+Cl_2$

$NaOH+HCl\to NaCl+H_2O$

5)

$MgCO_3+H_2SO_4\to MgSO_4+CO_2+H_2O$

$MgSO_4+BaCl_2\to BaSO_4+MgCl_2$

$MgCl_2+2NaOH\to Mg(OH)_2+2NaCl$

$Mg(OH)_2+2HNO_3\to Mg(NO_3)_2+2H_2O$

6)

$CuO+2HCl\to CuCl_2+H_2O$

$CuCl_2+2AgNO_3\to Cu(NO_3)_2+2AgCl$

7)

$Fe+2HCl\to FeCl_2+H_2$

$FeCl_2+2AgNO_3\to Fe(NO_3)_2+2AgCl$

$Fe(NO_3)_2+Mg\to Mg(NO_3)_2+Fe$

8)

$2Al+6HCl\to 2AlCl_3+3H_2$

$AlCl_3+3NaOH\to Al(OH)_3+3NaCl$

$2Al(OH)_3\xrightarrow{{t^o}} Al_2O_3+3H_2O$

$Al_2O_3+3H_2SO_4\to Al_2(SO_4)_3+3H_2O$

Đáp án:

Giải thích các bước giải:

 `1,`

`CuSO_4+2NaOH->Cu(OH)_2+Na_2SO_4`

$Cu(OH)_2\xrightarrow{t^o}CuO+H2O$

$CuO+H_2\xrightarrow{t^o}Cu+H_2O$

`2,`

`Na_2O+H_2O->2NaOH`

`NaOH+HCl->NaCl+H_2O`

`NaCl+AgNO_3->AgCl+NaNO_3`

`3,`

`MgCl_2+2AgNO_3->2AgCl+Mg(NO_3)_2`

`Mg(NO_3)_2+2NaOH->NaNO_3+Mg(OH)_2`
$Mg(OH)_2\xrightarrow{t^o}MgO+H_2O$

`MgO+H_2SO_4->MgSO_4+H_2O`

`4, Na_2CO_3+HCl->NaCl+NaHCO_3`

$2NaCl+2H_2O\xrightarrow{đpmn}2NaOH+Cl_2+H_2$

`NaOH+HCl->NaCl+H_2O`

`Na_2CO_3+Ba(OH)_2->BaCO_3+2NaOH`

`2NaOH+CO_2->Na_2CO_3+H_2O`

`5,`

`MgCO_3+H_2SO_4->MgSO_4+CO_2+H_2O`

`MgSO_4+BaCl_2->BaSO_4+MgCl_2`

`MgCl_2+2NaOH->Mg(OH)_2+2NaCl`

`Mg(OH)_2+HNO_3->Mg(NO_3)-2+2H_2O`

`6, CuO+2HCl->CuCl_2+H-2O`

`CuCl_2+2AgNO_3->2AgCl+Cu(NO_3)_2`

`7, Fe+2HCl->FeCl_2+H_2`

`FeCl_2+2AgNO_3->Fe(NO_3)_2+2AgCl`

`Fe(NO_3)_2+Mg->Mg(NO_3)_2+Fe`

`8, 2Al+6HCl->2AlCl_3+3H_2`

`AlCl_3+3NaOH->Al(OH)_3+3NaCl`

$2Al(OH)_3\xrightarrow{t^o}Al_2O_3+3H_2O$

`Al_2O_3+3H_2SO_4->Al_2(SO_4)_3+3H_2O`