$\begin{array}{l} P = \dfrac{{x + \sqrt x }}{{x - 2\sqrt x  + 1}}:\left( {\dfrac{{\sqrt x  + 1}}{{\sqrt x }} - \dfrac{1}{{1 - \sqrt x }} + \dfrac{{2 - x}}{{x - \sqrt x }}} \right)\\ P = \dfrac{{\sqrt x \left( {\sqrt x  + 1} \right)}}{{{{\left( {\sqrt x  - 1} \right)}^2}}}:\left( {\dfrac{{\left( {\sqrt x  + 1} \right)\left( {1 - \sqrt x } \right) - \sqrt x  - 2 + x}}{{\sqrt x \left( {1 - \sqrt x } \right)}}} \right)\\ P = \dfrac{{\sqrt x \left( {\sqrt x  + 1} \right)}}{{{{\left( {\sqrt x  - 1} \right)}^2}}}:\dfrac{{1 - x - \sqrt x  - 2 + x}}{{\sqrt x \left( {1 - \sqrt x } \right)}}\\ P = \dfrac{{\sqrt x \left( {\sqrt x  + 1} \right)}}{{{{\left( {\sqrt x  - 1} \right)}^2}}}.\dfrac{{\sqrt x \left( {1 - \sqrt x } \right)}}{{ - \left( {\sqrt x  + 1} \right)}}\\ P = \dfrac{{\sqrt x \left( {\sqrt x  + 1} \right)}}{{{{\left( {\sqrt x  - 1} \right)}^2}}}.\dfrac{{\sqrt x \left( {\sqrt x  - 1} \right)}}{{\sqrt x  + 1}} = \dfrac{x}{{\sqrt x  - 1}} \end{array}$