Em tham khảo nha:

\(\begin{array}{l}
a)\\
m = 150 \times 65 \times 1,6605 \times {10^{ - 24}} = 1,62 \times {10^{ - 20}}(g)\\
b)\\
m = 50 \times 198 \times 1,6605 \times {10^{ - 24}} = 1,64 \times {10^{ - 20}}(g)\\
c)\\
{n_{Pb}} = \dfrac{{12 \times {{10}^{23}}}}{{6 \times {{10}^{23}}}} = 2\,mol\\
{m_{Pb}} = 2 \times 207 = 414g\\
d)\\
{n_{F{e_2}{{(S{O_4})}_3}}} = \dfrac{{36 \times {{10}^{23}}}}{{6 \times {{10}^{23}}}} = 6\,mol\\
{m_{F{e_2}{{(S{O_4})}_3}}} = 6 \times 400 = 2400g\\
e)\\
{n_{Mn}} = \dfrac{{320}}{{55}} = \dfrac{{64}}{{11}}\,mol\\
{A_{Mn}} = \dfrac{{64}}{{11}} \times 6 \times {10^{23}} = 3,49 \times {10^{24}}\\
f)\\
{n_{A{l_2}{O_3}}} = \dfrac{{160}}{{102}} = \dfrac{{80}}{{51}}\,mol\\
{A_{A{l_2}{O_3}}} = \dfrac{{80}}{{51}} \times 6 \times {10^{23}} = 9,41 \times {10^{23}}
\end{array}\)