Em tham khảo nha :

\(\begin{array}{l}
2)\\
{M_c} = 1,9926 \times {10^{ - 23}}g\\
1dvC = \dfrac{{1,9926 \times {{10}^{ - 23}}}}{{12}} = 1,6605 \times {10^{ - 24}}g\\
1g = \dfrac{1}{{1,6605 \times {{10}^{ - 24}}}} = 6,02228 \times {10^{23}}dvC\\
3)\\
{M_{Cu}} = 64dvC\\
{m_{Cu}} = 64 \times 1,6605 \times {10^{ - 24}} = 1,06272 \times {10^{ - 22}}g\\
4)\\
{M_{Fe}} = 56dvC\\
{m_{Fe}} = 50 \times 56 \times 1,6605 \times {10^{ - 24}} = 4,6494 \times {10^{ - 21}}g\\
5)\\
{n_{Al}} = \dfrac{{3 \times {{10}^{23}}}}{{6 \times {{10}^{23}}}} = 0,5mol\\
{m_{Al}} = 0,5 \times 27 = 13,5g\\
6)\\
{n_{CuS{O_4}}} = \dfrac{{6 \times {{10}^{23}}}}{{6 \times {{10}^{23}}}} = 1mol\\
{m_{CuS{O_4}}} = 1 \times 160 = 160g\\
7)\\
{n_{Cu}} = \dfrac{{32}}{{64}} = 0,5mol\\
{N_{Cu}} = 0,5 \times 6 \times {10^{23}} = 3 \times {10^{23}}\text{(Nguyên tử)}\\
8)\\
{n_{F{e_2}{O_3}}} = \dfrac{{160}}{{160}} = 1mol\\
{N_{F{e_2}{O_3}}} = 1 \times 6 \times {10^{23}} = 6 \times {10^{23}}\text{(Phân tử)}
\end{array}\)