Em tham khảo nha :

\(\begin{array}{l}
22)\\
Mg + 2HCl \to MgC{l_2} + {H_2}\\
A{l_2}{O_3} + 6HCl \to 2AlC{l_3} + 3{H_2}O\\
hh:Mg(a\,mol);A{l_2}{O_3}(b\,mol)\\
\left\{ \begin{array}{l}
a + 6b = 0,8\\
95a + 267b = 36,2
\end{array} \right.\\
 \Rightarrow a = 0,012;b = 0,1313\\
{m_{Mg}} = 0,012 \times 24 = 0,288g\\
{m_{A{l_2}{O_3}}} = 0,1313 \times 102 = 13,396g\\
m = 0,288 + 13,396 = 13,684g\\
23)\\
A\\
{n_f} = \dfrac{9}{{180}} = 0,05mol\\
{n_g}:{n_f} = 2:1\\
 \Rightarrow {n_g} = 2{n_f} = 0,1mol\\
\text{Trong môi trường kiềm thì fructozo sẽ chuyển hóa thành glucozo}\\
 \Rightarrow {n_{{C_6}{H_{12}}{O_6}}} = {n_g} + {n_f} = 0,15mol\\
{C_6}{H_{12}}{O_6} + 2AgN{O_3} + 3N{H_3} + {H_2}O \to 2Ag + 2N{H_4}N{O_3} + {C_6}{H_{12}}{O_7}\\
{n_{Ag}} = 2{n_{{C_6}{H_{12}}{O_6}}} = 0,3mol\\
{m_{Ag}} = 0,3 \times 108 = 32,4g
\end{array}\)

bn xem hình