Đáp án:

Giải thích các bước giải:

mHgo=52,55-20=32,55 gam

nHgo=32,55:217=0,15 mol

%mMgo=(20:52,55).100%=38,06%

%mHgo=100%-38,06%=61,94%

a,   h2+hgo--->h2o+hg

    0,15  0,15             0,15       mol

Vh2=0,15.22,4=3,36 lít

m kim loại=mHg=0,15.201=30,15 gam

b,  nZn=nh2=0,15 mol

mZn=0,15.65=9,75 gam

`m_{MgO}=20g`

`=> m_{HgO}=52,55-20=32,55g`

`=> n_{HgO}=\frac{32,55}{217}=0,15(mol)`

`n_{MgO}=\frac{20}{24+16}=0,5(mol)`

`a)` `HgO+H_2\overset{t^o}{\to}Hg+H_2O`

`n_{H_2}=n_{HgO}=0,15(mol)`

`V_{H_2}=0,15.22,4=3,36(l)`

`%m_{MgO}=\frac{20.100%}{52,55}\approx 61,44%`

`%m_{HgO}=100%-61,44%=38,56%`

`n_{Hg}=n_{H_2}=0,15(mol)`

`=> m_{Hg}=201.0,15=30,15g`

`b)` `Zn+2HCl\to ZnCl_2+H_2`

`n_{Zn}=n_{H_2}=0,15(mol)`

`=> m_{Zn}=0,15.65=9,75g`