Đáp án:

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Giải thích các bước giải:

\(\begin{array}{l}
1.\\
2C{H_3}{\rm{COO}}H + CaC{O_3} \to {(C{H_3}{\rm{COO}})_2}Ca + {H_2}O + C{O_2}\\
{C_6}{H_{12}}{O_6} + 2AgN{O_3} + {H_2}O + 2N{H_3} \to 2Ag + 2N{H_4}N{O_3} + {C_6}{H_{12}}{O_7}
\end{array}\)

\(\begin{array}{l}
2.\\
{C_2}{H_4} + {H_2}O \to {C_2}{H_5}OH\\
{C_2}{H_5}OH + {O_2} \to C{H_3}{\rm{COO}}H + {H_2}O\\
C{H_3}{\rm{COO}}H + {C_2}{H_5}OH \to C{H_3}{\rm{COO}}{C_2}{H_5} + {H_2}O\\
C{H_3}{\rm{COO}}{C_2}{H_5} + NaOH \to C{H_3}{\rm{COO}}Na + {C_2}{H_5}OH
\end{array}\)

\(\begin{array}{l}
3.\\
a,{C_2}{H_5}OH + 3{O_2} \to 2C{O_2} + 3{H_2}O\\
b,\\
{n_{{C_2}{H_5}OH}} = 0,2mol\\
 \to {n_{C{O_2}}} = 2{n_{{C_2}{H_5}OH}} = 0,4mol\\
 \to {m_{C{O_2}}} = 17,6g\\
 \to {n_{{H_2}O}} = 3{n_{{C_2}{H_5}OH}} = 0,6mol\\
 \to {m_{{H_2}O}} = 10,8g
\end{array}\)