@Linh3782142

Giải thích các bước giải:

`A=((-5)/11)``.``7/15``.``(11/(-5)).(-30)`

`A=[((-5)/11)``.``(11/(-5))][7/15``.``(-30)`$]$

`A=1.(-14)`

`A=``-14`

________________________

`B=(-1/6)``.``(-15/19)``.``38/45`

`B=((-1).(-15).38)/(6.19.45)`

`B=((-1).(-15).2.19)/(6.19.15.3)`

`B=((-1).(-1).2)/(6.3)`

`B=2/18`

`B=1/9`

_______________________

`D=(2``2/15``.``9/17``.``3/32):(-3/17)`

`D=(32/15``.``9/17``.``3/32)``.``(-17/3)`

`D=((32.9.3)/(15.17.32))``.``(-17/3)`

`D=((32.9.3)/(3.5.17.32))``.``(-17/3)`

`D=((1.9.1)/(1.5.17.1))``.``(-17/3)`

`D=9/85``.``(-17/3)`

`D=(9.(-17))/(85.3)`

`D=(3.3.(-17))/(17.5.3)`

`D=(3.(-1))/(1.5)`

`D=(-3)/5`

$A=\left(\dfrac{-5}{11}\right).\dfrac{7}{15}.\left(\dfrac{11}{-5}\right).\left(-30\right)\\
=\left[\left(\dfrac{-5}{11}\right)\left(\dfrac{11}{-5}\right)\right]\left[\dfrac{7}{15}.\left(-30\right)\right]\\
=1.\left(-14\right)\\
=-14\\
B=\left(-\dfrac{1}{6}\right).\left(-\dfrac{15}{19}\right).\dfrac{38}{45}\\
=\dfrac{1}{6}.\dfrac{15}{19}.\dfrac{38}{45}\\
=\dfrac{1.15.38}{6.19.45}\\
=\dfrac{1.15.19.2}{2.3.19.15.3}\\ =\dfrac{1}{3.3}\\ =\dfrac{1}{9}\\
C=\left(\dfrac{-5}{9}\right).\dfrac{3}{11}+\left(-\dfrac{13}{18}\right).\dfrac{3}{11}\\
=\left[\left(\dfrac{-5}{9}\right)+\left(-\dfrac{13}{18}\right)\right].\dfrac{3}{11}\\
=\left(\dfrac{-10}{18}+\dfrac{-13}{18}\right).\dfrac{3}{11}\\
=\dfrac{-23}{18}.\dfrac{3}{11}\\
=\dfrac{-69}{198}\\
=-\dfrac{23}{66}\\
D=\left(2\dfrac{2}{15}.\dfrac{9}{17}.\dfrac{3}{32}\right):\left(-\dfrac{3}{17}\right)\\
=\dfrac{32}{15}.\dfrac{9}{17}.\dfrac{3}{32}.\dfrac{-17}{3}\\ =-\dfrac{32.9.3.17}{15.17.32.3}\\
=-\dfrac{9}{15}\\
=-\dfrac{3}{5}$