Đáp án:

Bạn tham khảo~

`a) + b) + c)`

Hợp chất:

`PTK_{KOH}=39 + 16 + 1= 56 (đvC)`

`PTK_{H_2SO_4}=1 × 2 + 32 + 16 × 4= 98 (đvC)`

`PTK_{Fe_2(CO_3)_3=56 × 2 + (12 + 16 × 3) × 3= 292 (đvC)`

`PTK_{BaSO_4}=137 + 32 + 16 × 4= 233 (đvC)`

`PTK_{Ca(OH)_2}=40 + (16 + 1) × 2= 74 (đvC)`

`PTK_{HCl}=1 + 35,5= 36,5 (đvC)`

`PTK_{NO}=14 + 16= 30 (đvC)`

`PTK_{NH_3}=14 + 1 × 3= 17 (đvC)`

`PTK_{C_6H_5OH}=12 × 6 + 1 × 5 + 16 + 1= 94 (đvC)`

`PTK_{CH_4}=12 + 1 × 4= 16 (đvC)`

`PTK_{BaO}=137 + 16= 153 (đvC)`

Đơn chất:

`PTK_C= 12 (đvC)`

`PTK_{Cl_2}=35,5 × 2= 71 (đvC)`

`PTK_{O_2}=16 × 2= 32 (đvC)`

`PTK_{Fe}= 56 (đvC)`

`PTK_{Br_2}=80 × 2= 160 (đvC)`

`PTK_{K}= 39 (đvC)`

`PTK_{O_3}=16 × 3= 48 (đvC)`

Giải thích các bước giải:

`a)`

`@\ Don\ ch at :`

`+\ C\ (PTK=12đvC)`

`+\ Cl_2\ (PTK=35,5.2=71đvC)`

`@\ H o p\ ch at :`

`+\ KOH\ (PTK=39+17=56đvC)`

`+\ H_2SO_4\ (PTK=1.2+32+16.4=98đvC)`

`+\ Fe(CO_3)_3\ (PTK=56+12.3+16.9=236đvC)`

`b)`

`@\ Don\ ch at :`

`+\ O_2\ (PTK=16.2=32đvC)`

`+\ Fe\ (PTK=56đvC)`

`@\ H o p\ c h a t:`

`+\ BaSO_4\ (PTK=137+32+16.4=233đvC)`

`+\ Ca(OH)_2\ (PTK=40+17.2=74đvC)`

`c)`

`@\ Don\ ch at :`

`+\ Br_2\ (PTK=80.2=160đvC)`

`+\ K\ (PTK=39đvC)`

`@\ H o p\ c h a t:`

`+\ HCl\ (PTK=1+35,5=36,5đvC)`

`+\ NO\ (PTK=14+16=30đvC)`

`+\ NH_3\ (PTK=14+1.3=17đvC)`

`d)`

`@\ Don\ ch at :`

`+\ O_3\ (PTK=16.3=48đvC)`

`@\ H o p\ c h a t:`

`+\ C_6H_5OH\ (PTK=12.6+1.5+17=94đvC)`

`+\ CH_4\ (PTK=12+1.4=16đvC)`

`+\ BaO\ (PTK=137+16=153đvC)`