Đáp án:

Giải thích các bước giải:

mC=12*nco2=12*0.1=1.2

mH=2*nH2O=2*0.1=0.2

=>mC++mH=1.2+0.2=1..4=mA

nen A la hidrocaccbon(C vs  H)

goij ctttq cua A laaff CxHy

d(A/N2)=2

=> M (A)=28dvc

12x/mC=1y/mH=M(A)/mA

=>12x/1.2=y/0.2=28/1.4

x=2

y=4

ctpt la c2h4

vote 5s  cho mk vs nha

Em tham khảo nha :

\(\begin{array}{l}
a)\\
CTPT:{C_x}{H_y}\\
{n_{C{O_2}}} = \dfrac{{4,4}}{{44}} = 0,1mol\\
{n_{{H_2}O}} = \dfrac{{1,8}}{{18}} = 0,1mol\\
{M_A} = 2{M_{{N_2}}} = 2 \times 28 = 56dvC\\
{n_A} = \dfrac{{1,4}}{{56}} = 0,025mol\\
{n_C} = {n_{C{O_2}}} = 0,1mol\\
{n_H} = 2{n_{{H_2}O}} = 0,1mol\\
x = \dfrac{{{n_C}}}{{{n_A}}} = \dfrac{{0,1}}{{0,025}} = 4\\
y = \dfrac{{{n_H}}}{{{n_A}}} = \dfrac{{0,2}}{{0,025}} = 8\\
 \Rightarrow CTPT:{C_4}{H_8}\\
b)\\
CTCT:\\
C{H_2} = CH - C{H_2} - C{H_3}\\
C{H_3} - CH = CH - C{H_3}
\end{array}\)