Code

lst = [int(x) for x in input().split()]
lst_set = list(set(lst))
if len(lst_set) == 1: print(1)
elif len(lst_set) == 2 and (lst.count(lst_set[0]) == 4 or lst.count(lst_set[0]) == 1): print(2)
elif len(lst_set) == 2 and (lst.count(lst_set[0]) == 3 or lst.count(lst_set[0]) == 2): print(3)
elif len(lst_set) == 3 and (lst.count(lst_set[0]) == 3 or lst.count(lst_set[1]) == 3 or lst.count(lst_set[2]) == 3): print(4)
elif len(lst_set) == 3: print(5)
elif len(lst_set) == 4: print(6)
elif len(lst_set) == 5: print(7)

Note: Ừ thì...nó cũng là if else đến chết thôi :))

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def sc(lst):
    s = set(lst)
    sl = 0
    for i in s:
        if (lst.count(i) == 2):
            sl+=1
    return sl
def dk(*v):
    for i in v:
        if (eval(i[0])):
            print(i[1])
            break
so = list(sorted(map(int,input().split())))
dk(['so[0] == so[4]',1], ['so[0] == so[3] or so[1] == so[4]',2], ['so[0] == so[1] and so[2] == so[4]',3], ['so[0] == so[2] and so[3] == so[4]',3], ['so[0] == so[2] and so[3] != so[4]',4], ['so[0] != so[1] and so[2] == so[4]',4], ['sc(so) == 2',5], ['sc(so) == 1',6], ['len(set(so)) == 5',7])

$\\$

`@Daoanhviet96`