`a,`

PTHH:

`2Fe+3Cl_2`$\xrightarrow[]{t^o}$`2FeCl_3`

`Ca+Cl_2`$\xrightarrow[]{t^o}$`CaCl_2`

`FeCl_3+3NaOH->Fe(OH)_3↓+3NaCl`

`b,`

`n_{Cl_2}=(5,6)/(22,4)=0,25(mol)`

`n_{Fe(OH)_3}=(10,7)/(107)=0,1(mol)`

Từ PTHH :

`n_{Fe}=n_{FeCl_3}=n_{Fe(OH)_3}=0,1(mol)`

`=>m_{Fe}=0,1.56=5,6(g)`

Mặt khác theo PTHH :

` 3/2 n_{Fe} + n_{Ca}=n_{Cl_2}`

`=> 3/2 . 0,1 + n_{Ca}=0,25`

`=>n_{Ca}=0,1(mol)`

`=>m_{Ca}=0,1.40=4(g)`

`=>m_{A}=5,6+4=9,6(g)`

`-----`

`\%m_{Fe}=(5,6)/(9,6).100\%≈58,33\%`

`\%m_{Ca}=(100-58,33)\%=41,67\%`

`#Ly`

$a)$

PTHH:

$(1):$ $2Fe$ $+$ $3Cl_2$ $\xrightarrow[]{t^o}$ $2FeCl_3$

$(2):$ $Ca$ $+$ $Cl_2$ $\xrightarrow[]{t^o}$ $CaCl_2$

$(3):$ $FeCl_3$ $+$ $3NaOH$ $+$ $Fe(OH)_3↓$ $+$ $3NaCl$

$b)$

`n_(Cl_2` `=` `(V)/(22,4)` `=` `(5,6)/(22,4)=0,25` $(mol)$

`n_(Fe(OH)_3` `=` `m/M` `=` `(10,7)/(107)=0,1` $(mol)$

Theo PT $(3)$, `n_(FeCl_3` `=` `n_(Fe(OH)_3` `=` `0,1` $(mol)$

Theo PT $(1)$, `n_(Fe` `=` `n_(FeCl_3` `=` `0,1` $(mol)$

`m_(Fe` `=` `n.M=0,1.56=5,6` $(g)$

Theo PT $(1)$, `n_(Cl_2` `=` `(3)/(2)n_(FeCl_3` `=` `0,15` $(mol)$

`n_(Cl_2(2)` `=` `0,25-0,15=0,1` $(mol)$

Theo PT $(2)$, `n_(Ca` `=` `n_(Cl_2` `=` `0,1` $(mol)$

`m_(Ca` `=` $0,1.40=4$ $(g)$

`m_A` `=` `5,6+4=9,6` $(g)$

`%m_(Fe(A)` `=` `(m_{Fe})/(m_A).100%` `=` `(5,6)/(9,6).100%≈58,33%`

`%m_(Ca(A)` `=` `100-58,33=41,67%`