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\(\begin{array}{l}
1)\\
a)\\
2KCl{O_3} \xrightarrow{t^0} 2KCl + 3{O_2}\\
b)\\
{n_{{O_2}}} = \dfrac{V}{{22,4}} = \dfrac{{13,44}}{{22,4}} = 0,6mol\\
{n_{KCl{O_3}}} = \dfrac{2}{3}{n_{{O_2}}} = 0,4mol\\
{m_{KCl{O_3}}} = n \times M = 0,4 \times 122,5 = 49g\\
2)\\
a)\\
2KMn{O_4} \xrightarrow{t^0} {K_2}Mn{O_4} + Mn{O_2} + {O_2}\\
b)\\
{n_{KMn{O_4}}} = \dfrac{m}{M} = \dfrac{{79}}{{158}} = 0,5mol\\
{n_{{O_2}}} = \dfrac{{{n_{KMn{O_4}}}}}{2} = 0,25mol\\
{V_{{O_2}}} = n \times 22,4 = 0,25 \times 22,4 = 5,6l\\
c)\\
3Fe + 2{O_2} \xrightarrow{t^0} F{e_3}{O_4}\\
{n_{Fe}} = \dfrac{3}{2}{n_{{O_2}}} = 0,375mol\\
{m_{Fe}} = n \times M = 0,375 \times 56 = 21g\\
{n_{F{e_3}{O_4}}} = \dfrac{1}{2}{n_{{O_2}}} = 0,125mol\\
{m_{F{e_3}{O_4}}} = n \times M = 0,125 \times 232 = 29g
\end{array}\)