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 Đáp án `a) -5/3`

`b) 49/16`

`c) -7/2`

`d) 1/8`

`e) -3`

`f) x in {0 ; 3}`

Các bước giải

`a) x : ( -3/5 )^2 = -3/5`

`=> x = ( -3/5 )^1 : ( -3/5 )^2`

`=> x = ( -3/5 )^( 1 - 2 )`

`=> x = ( -3/5 )^-1`

`=> x = -5/3`

Vậy ` x = -5/3`

`b) ( 4/7 )^4 : x = ( 4/7 )^6`

`=> x = ( 4/7 )^4 : ( 4/7 )^6`

`=> x = ( 4/7 )^( 4 - 6 )`

`=> x = ( 4/7 )^-2`

`=> x = 49/16`

Vậy `x = 49/16`

`c) ( x - 1/2 )^3 = -64`

`=> x - 1/2 = -4`

`=> x = -4 + 1/2`

`=> x = -7/2`

Vậy `x = -7/2`

`d) ( 1/2 )^2 . x = ( 1/2 )^5`

`=> x = ( 1/2 )^5 : ( 1/2 )^2`

`=> x = ( 1/2 )^( 5 - 2 )`

`=> x = ( 1/2 )^3`

`=> x = 1/8`

Vậy ` x = 1/8`

`e) ( -1/3 )^3 . x = 1/81`

`=> -1/27 . x = 1/81`

`=> x = -1/27 : 1/81`

`=> x= -3`

Vậy `x = -3`

`f) ( 3 - 2x )^2  = 9`

`=> 3 - 2x = +-3`

`=>` $\left[\begin{matrix} 3-2x=3\\ 3-2x=-3\end{matrix}\right.$

`=>` $\left[\begin{matrix} 2x=3-3\\ 2x=3-(-3)\end{matrix}\right.$

`=>` $\left[\begin{matrix} 2x=0\\ 2x=6\end{matrix}\right.$

`=>` $\left[\begin{matrix} x=0:2\\ x=6:2\end{matrix}\right.$

`=>` $\left[\begin{matrix} x=0\\ x=3\end{matrix}\right.$

Vậy `x in {0 ; 3}`