Câu 3: 

$CH_4+2O_2\buildrel{{t^o}}\over\to CO_2+2H_2O$

$2C_2H_2+5O_2\buildrel{{t^o}}\over\longrightarrow 4CO_2+ 2H_2O$

$C_2H_6O+3O_2\buildrel{{t^o}}\over\to 2CO_2+3H_2O$

Câu 4:

a,

$n_P=\dfrac{46,5}{31}=1,5(mol)$

$4P+5O_2\buildrel{{t^o}}\over\to 2P_2O_5$

$\Rightarrow n_{O_2}=\dfrac{5}{4}n_P=1,875(mol)$

$\to V_{O_2}=1,875.22,4=42l$

b,

$n_{Al}=\dfrac{67,5}{27}=2,5(mol)$

$4Al+3O_2\buildrel{{t^o}}\over\to 2Al_2O_3$

$\Rightarrow n_{O_2}=\dfrac{3}{4}n_{Al}=1,875(mol)$

$\to V_{O_2}=1,875.22,4=42l$

c,

$n_{H_2}=\dfrac{33,6}{22,4}=1,5(mol)$

$2H_2+O_2\buildrel{{t^o}}\over\to 2H_2O$

$\Rightarrow n_{O_2}=\dfrac{n_{H_2}}{2}=0,75(mol)$

$\to V_{O_2}=0,75.22,4=16,8l$

Đáp án:

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