Đáp án:

$x-\dfrac{11}{6}=\dfrac{1}{5}$

$⇒ x= \dfrac{1}{5}+\dfrac{11}{6}$

$⇒ x= \dfrac{6}{30}+\dfrac{55}{30}$

$⇒ x= \dfrac{6+55}{30}$

$⇒ x= \dfrac{61}{30}$

$\text{Vậy x= $\dfrac{61}{30}$}$

$\text{_________________________}$

`(2x+\frac{3}{5})^2-\frac{9}{25}=0`

`⇒(2x+\frac{3}{5})^2= \frac{9}{25}`

`⇒ (2x+\frac{3}{5})^2= (±\frac{3}{5})^2`

$\text{Xét 2 Trường hợp:}$

`TH1: 2x+\frac{3}{5}=\frac{3}{5}`

`⇒ 2x= \frac{3}{5}-\frac{3}{5}`

`⇒2x=0`

$⇒x=0$

`TH2: 2x+\frac{3}{5}= -\frac{3}{5}$

`⇒2x= (-\frac{3}{5})-\frac{3}{5}`

`⇒2x= \frac{6}{5}`

`⇒ x= \frac{6}{5}:2$

$⇒ x= \dfrac{3}{5}$

$\text{Vậy x ∈ {$\dfrac{3}{5};0}}$

Đáp án:

Giải thích các bước giải:

 `x- 11/6=1/5`

`x= 1/5+11/6`

`x=6/30+ 55/30`

`x=61/30`

Vậy `x= 61/30`

_________________________________-

`(2x+ 3/5)^2-9/25= 0`

`(2x+ 3/5)^2=0+ 9/25`

`(2x+ 3/5)^2= 9/25`

`TH1: 2x+ 3/5= 3/5`

`2x= 3/5- 3/5`

`2x= 0`

`x= 0`

`TH2: 2x+ 3/5= -3/5`

`2x= -3/5- 3/5`

`2x=-6/5`

`x=-6/5: 2`

`x=-3/5`

Vậy `x∈ { 0; -3/5}`