Đáp án + Giải thích các bước giải:

 $(1) CH_3COONa + NaOH \xrightarrow{CaO, t^o}{\longrightarrow} CH_4 + Na_2CO_3$

$(2) Al_4C_3  + 12H_2O \longrightarrow 4Al(OH)_3 \downarrow + 3CH_4$

$(3) 2CH_4 \xrightarrow[\text{ làm lạnh nhanh}]{1500^oC} C_2H_2 + 3H_2$

$(4) C_2H_2 + H_2 \xrightarrow{Pd/PbCO_3, t^o} C_2H_4$

$(5) C_2H_4 + HBr \longrightarrow C_2H_5Br$

$(6) C_2H_5Br + NaOH \longrightarrow C_2H_5OH + NaBr$

$(7) C_2H_5OH \xrightarrow{H_2SO_4\text{ đặc}, 180^oC} C_2H_4 + H_2O$

$(8) C_2H_5OH + HCl_{\text{ đặc}} \longrightarrow C_2H_5Cl + H_2O$

$(9) C_2H_5Cl + KOH \xrightarrow{t^o, C_2H_5OH} KCl + C_2H_4 + H_2O$

$(10) 2C_2H_5OH \xrightarrow{H_2SO_4\text{ đặc}, 140^oC} C_2H_5OC_2H_5 + H_2O$

$(11) C_2H_5OH + CuO \overset{t^o}{\longrightarrow} Cu + CH_3CHO + H_2O$

Các phản ứng xảy ra:

\(C{H_3}COONa + NaOH\xrightarrow{{CaO,{t^o}}}C{H_4} + N{a_2}C{O_3}\)

\(A{l_4}{C_3} + 12{H_2}O\xrightarrow{{}}4{\text{A}}l{(OH)_3} + 3C{H_4}\)

\(2C{H_4}\xrightarrow{{{{1500}^o}C,lln }}{C_2}{H_2} + 3{H_2}\)

\({C_2}{H_2} + {H_2}\xrightarrow{{P{\text{d}},PbC{O_3}/{t^o}}}{C_2}{H_4}\)

\({C_2}{H_4} + HB{\text{r}}\xrightarrow{{}}{C_2}{H_5}B{\text{r}}\)

\({C_2}{H_5}B{\text{r}} + NaOH\xrightarrow{{}}{C_2}{H_5}OH + NaB{\text{r}}\)

\({C_2}{H_5}OH\xrightarrow{{{H_2}S{O_4},{{180}^o}C}}{C_2}{H_4} + {H_2}O\)

\({C_2}{H_5}OH + HCl\xrightarrow{{}}{C_2}{H_5}Cl + {H_2}O\)

\({C_2}{H_5}Cl + KOH\xrightarrow{{ancol}}{C_2}{H_4} + KCl + {H_2}O\)

\(2{C_2}{H_5}OH\xrightarrow{{{H_2}S{O_4}/{{140}^o}C}}{C_2}{H_5}O{C_2}{H_5} + {H_2}O\)

\({C_2}{H_5}OH + 2CuO\xrightarrow{{{t^o}}}C{H_3}CHO + C{u_2}O + {H_2}O\)