`b)` `(x - 1)/x + 5/2 = (3x)/{2(x - 1)}` (đkxđ: `x\ne 0; x \ne 1`)

`<=> {2(x - 1)(x - 1)}/{2x(x - 1)} + {5x(x - 1)}/{2x(x - 1)} = (3x^2)/{2x(x - 1)}`

`=> 2x - 2 + 5x^2 - 5x = 3x^2`

`<=> 5x^2 - 3x^2 + 2x - 5x - 2 = 0`

`<=> 2x^2 - 3x - 2 = 0`

`<=> (2x^2 - 4x) + (x - 2) = 0`

`<=> 2x(x - 2) + (x - 2) = 0`

`<=> (x - 2)(2x + 1) = 0`

`<=>` \(\left[ \begin{array}{l}x-2=0\\2x+1=0\end{array} \right.\) 

`<=>` \(\left[ \begin{array}{l}x=2(tm)\\x= \dfrac{-1}{2}(tm) \end{array} \right.\)

Vậy pt có tập nghiệm `S = {2; -1/2}`

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$\text{@Bulletproof Boy Scout}$

$#Rosé$

`b) ( x - 1 )/x + 5/2 = ( 3x )/( 2 ( x - 1 )) `

` ĐKXĐ : x \ne 1 ; x \ne 0 `

`<=> ( 2 ( x - 1 ) ( x - 1 ))/( 2x ( x - 1 )) + ( 5x ( x - 1 ))/( 2x ( x - 1 )) = ( 3x^2 )/( 2x ( x - 1 )) `

`=> 2 ( x - 1) ( x - 1 ) + 5x ( x - 1 ) = 3x^2 `

`<=> 2 ( x^2 - 2x + 1 ) + 5x^2 - 5x = 3x^2 `

`<=> 2x^2 - 4x + 2 + 5x^2 - 5x = 3x^2 `

`<=> 7x^2 - 9x + 2 = 3x^2 `

`<=> 7x^2 - 9x - 3x^2 = - 2 `

`<=> 4x^2 - 9x + 2 = 0 `

`<=> 4x^2 - 8x - x + 2 = 0 `

`<=> ( 4x^2 - 8x ) - ( x - 2 ) = 0 `

`<=> 4x ( x - 2 ) - ( x - 2 ) = 0 `

`<=> ( x - 2 ) ( 4x - 1 ) = 0 `

`<=>`\(\left[ \begin{array}{l}x-2=0\\4x-1=0\end{array} \right.\) 

`<=>`\(\left[ \begin{array}{l}x=2\\x= \dfrac{1}{4} \end{array} \right.\)

Vậy ` S = { 2 ; 1/4 } `