Bài 1:

a.

n Zn=$\frac{m}{M}$=$\frac{6,5}{65}$=0,1 mol

b.

n CaCO3=$\frac{m}{M}$=$\frac{10}{100}$=0,1 mol

c.

n CaO=$\frac{m}{M}$=$\frac{11,2}{56}$=0,2 mol

d.

n Ca(OH)2=CM.V=0,2.0,8=0,16 mol

Bài 2:

a.

m H2=n.M=0,2.2=1 g

b.

m O2=n.M=1,5.32=48 g

c.

n CO2=$\frac{V}{22,4}$=$\frac{16,8}{22,4}$=0,75 mol

m CO2=n.M=0,75.44=33 g

d.

n CH4=$\frac{V}{22,4}$=$\frac{26,88}{22,4}$=1,2 mol

m CH4=n.M=1,2.16=19,2 g

e.

m ct NaCl=$\frac{mdd.C}{100}$=$\frac{12.500}{100}$=60 g

----------------------Nguyễn Hoạt--------------------------

$Bài$ $1:$

$a)n_{Zn}=$ $\frac{6,5}{65}=0,1(mol)$

$b)n_{CaCO3}=$ $\frac{10}{100}=0,1(mol)$

$c)n_{CaO}=$ $\frac{11,2}{56}=0,2(mol)$

$c)n_{Ca(OH)2}=0,2.0,8=0,16(mol)$

$Bài$ $2:$

$a) m_{H2}=0,5.2=1(g)$

$b) m_{O2 }=1,5.32=48(g)$

$c) m_{CO2 }=0,75.44=33(g)$

$d) m_{CH4 }=1,2.16=19,2(g)$

$e) m_{ct_{ NaCL  } }=$$\frac{500.12}{100}=60(g)$       

$n_{NaCL }=$ $\frac{60}{58,5}=1(mol)$      

$ m_{NaCL }=1.58,5=58,5(g)$