PTHH:

`CH_4+Cl_2`$\xrightarrow[]{ánh sáng}$`CH_3Cl+HCl`

`CH_4+2O_2`$\xrightarrow[]{t^o}$`CO_2+2H_2O`

`CH_2=CH_2+H_2`$\xrightarrow[Ni]{t^o}$`C_2H_6`

`CH_2=CH_2+Br_2->CHBr-CHBr`

`CH_2=CH_2+HCl->C_2H_5Cl`

`CH_2=CH_2+H_2O`$\xrightarrow[H_2SO_4]{t^o}$`C_2H_5OH`

`nCH_2=CH_2→`$(\kern-6pt- CH_2-CH_2 -\kern-6pt)_n$

`CH≡CH+H_2`$\xrightarrow[Pd]{t^o}$`C_2H_4`

`CH≡CH+2H_2`$\xrightarrow[Ni]{t^o}$`C_2H_6`

`CH≡CH+2Br_2->CHBr_2-CHBr_2`

`CH≡CH+HCl->C_2H_3Cl`

`CH≡CH+H_2O`$\xrightarrow[HgSO_4]{t^o}$`CH_3CHO`

`CH≡CH+AgNO_3+2NH_3->Ag_2C_2+2NH_4NO_3`

Em tham khảo nha:

\(\begin{array}{l}
C{H_4} + C{l_2} \xrightarrow{as} C{H_3}Cl + HCl\\
C{H_4} + 2{O_2} \xrightarrow{t^0} C{O_2} + 2{H_2}O\\
C{H_2} = C{H_2} + {H_2} \xrightarrow{t^0,Ni} C{H_3} - C{H_3}\\
C{H_2} = C{H_2} + B{r_2} \to C{H_2}Br - C{H_2}Br\\
C{H_2} = C{H_2} + HCl \to C{H_3} - C{H_2}Cl\\
C{H_2} = C{H_2} + {H_2}O \xrightarrow{t^0,H_2SO_4} C{H_3} - C{H_2} - OH\\
nC{H_2} = C{H_2} \xrightarrow{t^0,xt} {( - C{H_2} - C{H_2} - )_n}\\
CH \equiv CH + {H_2} \xrightarrow{t^0,Pd} C{H_2} = C{H_2}\\
CH \equiv CH + 2{H_2} \xrightarrow{t^0,Ni} C{H_3} - C{H_3}\\
CH \equiv CH + 2B{r_2} \to CHB{r_2} - CHB{r_2}\\
CH \equiv CH + 2HCl \to C{H_2}Cl - C{H_2}Cl\\
CH \equiv CH + 2AgN{O_3} + 2N{H_3} \to A{g_2}{C_2} + 2N{H_4}N{O_3}
\end{array}\)