17/

$a,Zn+2HCl\xrightarrow{} ZnCl_2+H_2↑$

$b,P_2O_5+3H_2O\xrightarrow{} 2H_3PO_4$

$c,H_2O+Na_2O\xrightarrow{} 2NaOH$

$d,2H_2O+2K\xrightarrow{} 2KOH+H_2↑$

18/

$a,PTPƯ:Fe+2HCl\xrightarrow{} FeCl_2+H_2↑$

$b,n_{Fe}=\dfrac{11,2}{56}=0,2mol.$

$n_{HCl}=\dfrac{7,3}{36,5}=0,2mol.$

$\text{Lập tỉ lệ:}$ $\dfrac{0,2}{1}>\dfrac{0,2}{2}$

$⇒n_{Fe}$ $dư.$

$Theo$ $pt:$ $n_{FeCl_2}=\dfrac{1}{2}n_{HCl}=0,1mol.$

$⇒m_{FeCl_2}=0,1.127=12,7g.$

$c,Theo$ $pt:$ $n_{H_2}=\dfrac{1}{2}n_{HCl}=0,1mol.$

$⇒V_{H_2}=0,1.22,4=2,24l.$

$d,PTPƯ:Fe_2O_3+3H_2\xrightarrow{t^o} 2Fe+3H_2O$

$Theo$ $pt:$ $n_{Fe}=\dfrac{2}{3}n_{H_2}=\dfrac{1}{15}mol.$

$⇒m_{Fe}=\dfrac{1}{15}.56=3.73g.$

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