\(\begin{array}{l}
5)\\
Mg + {H_2}S{O_4} \to MgS{O_4} + {H_2}\\
Zn + {H_2}S{O_4} \to ZnS{O_4} + {H_2}\\
n{H_2} = \dfrac{{17,92}}{{22,4}} = 0,8\,mol\\
n{H_2}S{O_4} = n{H_2} = 0,8\,mol\\
BTKL\\
mhh + m{H_2}S{O_4} = m + m{H_2} \Rightarrow m = 108,3g\\
{C_M}{H_2}S{O_4} = \dfrac{{0,8}}{{0,15}} = 5,33M\\
6)\\
Mg + {H_2}S{O_4} \to MgS{O_4} + {H_2}\\
Fe + {H_2}S{O_4} \to FeS{O_4} + {H_2}\\
n{H_2} = \dfrac{{4,48}}{{22,4}} = 0,2\,mol\\
hh:Mg(a\,mol),Fe(b\,mol)\\
24a + 56b = 8\\
a + b = 0,2\\
 \Rightarrow a = b = 0,1\,mol\\
\% mFe = \dfrac{{0,1 \times 56}}{8} \times 100\%  = 70\% \\
\% mMg = 100 - 70 = 30\% \\
b)\\
m = mMgS{O_4} + mFeS{O_4} = 0,1 \times 120 + 0,1 \times 152 = 27,2g\\
c)\\
n{H_2}S{O_4} = n{H_2} = 0,2\,mol\\
 \Rightarrow V{H_2}S{O_4} = \dfrac{{0,2}}{2} = 0,1l
\end{array}\)

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