Đáp án + Giải thích các bước giải:

$a)MnO_2+4HCl\to MnCl_2+Cl_2\uparrow+2H_2O$

$Cl_2+H_2\xrightarrow{as}2HCl$

$2KMnO_4+16HCl\to 2KCl+2MnCl_2+5Cl_2\uparrow+8H_2O$

$Cl_2+Ca\xrightarrow{t^o}CaCl_2$

$CaCl_2+2H_2O\xrightarrow[cmn]{đpdd}Ca(OH)_2+Cl_2\uparrow+2H_2\uparrow$

$Ca(OH)_2+Cl_2\to CaOCl_2+H_2O$

$b)2KMnO_4+16HCl\to 2KCl+2MnCl_2+5Cl_2\uparrow+8H_2O$

$3Cl_2+6KOH\xrightarrow{t^o}5KCl+KClO_3+3H_2O$

$2KClO_3\xrightarrow[MnO_2]{t^o}2KCl+3O_2$

$2KCl+2H_2O\xrightarrow[cmn]{đpdd}2KOH+Cl_2\uparrow+H_2\uparrow$

$Cl_2+H_2O\leftrightharpoons HCl+HClO$

$2HClO\xrightarrow{as}2HCl+O_2$

$2HCl\xrightarrow{đpdd}H_2\uparrow+Cl_2\uparrow$

$2Fe+3Cl_2\xrightarrow{t^o}2FeCl_3$

$c)KClO_3+6HCl\to KCl+3Cl_2\uparrow+3H_2O$

$Cl_2+2NaOH\to NaCl+NaClO+H_2O$

$NaClO+2HCl\to NaCl+H_2O+Cl_2\uparrow$

$2NaCl\xrightarrow{đpnc}2Na+Cl_2\uparrow$

$Cl_2+2HBr\to 2HCl+Br_2$

$d)2NaCl+2H_2O\xrightarrow[cmn]{đpdd}2NaOH+Cl_2\uparrow+H_2\uparrow$

$NaOH+HCl\to NaCl+H_2O$

$2NaCl\xrightarrow{đpnc}Cl_2\uparrow+2Na$

$Cl_2+H_2O\leftrightharpoons HCl+HClO$

$2HClO\xrightarrow{as}2HCl+O_2$

$4HCl+MnO_2\to MnCl_2+Cl_2\uparrow+2H_2O$

$e)CaO+H_2O\to Ca(OH)_2$

$Ca(OH)_2+Cl_2\to CaOCl_2+H_2O$

$2CaOCl_2\xrightarrow{t^o,xt}2CaCl_2+O_2$

$CaCl_2\xrightarrow{đpnc}Ca+Cl_2\uparrow$

$Cl_2+2HBr\to 2HCl+Br_2$

$Br_2+2HI\to 2HBr+I_2$

Đáp án:

`↓`

Giải thích các bước giải:

`a)`

`-` `MnO_2``+``4HCl``→``MnCl_2``+``Cl_2↑``+``2H_2O`

`-` `H_2``+``Cl_2` $\xrightarrow[]{as}$ `2HCl`

`-` `2KMnO_4``+``16HCl``→``2KCl``+``2MnCl_2``+``5Cl_2↑``+``8H_2O`

`-` `Ca``+``Cl_2` $\xrightarrow[]{t^o}$ `CaCl_2`

`-` `CaCl_2``+``2H_2O` $\xrightarrow[cmn xốp]{đpdd}$ `Ca(OH)_2``+``Cl_2↑``+``2H_2↑`

`-` `2Ca(OH)_2``+``2Cl_2``→``Ca(OCl)_2``+``CaCl_2``+``2H_2O`

`b)`

`-` `2KMnO_4``+``16HCl``→``2KCl``+``2MnCl_2``+``5Cl_2↑``+``8H_2O`

`-` `3Cl_2``+`$6KOH_{đặc, nong}$ $\xrightarrow[]{t^o}$ `KClO_3``+``5KCl``+``3H_2O`

`-` `2KClO_3` $\xrightarrow[]{t^o}$ `2KCl``+``3O_2↑`

`-` `KCl``+``H_2O` $\xrightarrow[cmn]{đpdd}$ `KOH``+``Cl_2↑``+``H_2↑`

`-` `Cl_2``+``H_2O` $\rightleftharpoons$ `HClO``+``HCl`

`-` `2HClO` $\xrightarrow[]{as}$ `2HCl``+``O_2↑`

`-` `2HCl` $\xrightarrow[]{đpdd}$ `H_2``+``Cl_2`

`-` `2Fe``+``3Cl_2` $\xrightarrow[]{t^o}$ `2FeCl_3`

`c)`

`-` `KClO_3``+``6HCl``→``KCl``+``3Cl_2↑``+``3H_2O`

`-` `Cl_2``+``2NaOH``→``NaClO``+``NaCl``+``H_2O`

`-` `NaClO``+``2HCl` $\xrightarrow[]{đpdd}$ `NaCl``+``Cl_2↑``+``H_2O`

`-` `2NaCl` $\xrightarrow[]{đpnc}$ `2Na``+``Cl_2` 

`-` `Cl_2``+``2NaBr``+``2NaCl``+``Br_2`

`d)`

`-` `2NaCl``+``2H_2O` $\xrightarrow[cmn]{đpdd}$ `2NaOH``+``Cl_2↑``+``H_2↑`

`-` `NaOH``+``HCl``→``NaCl``+``H_2O`

`-` `2NaCl` $\xrightarrow[]{đpnc}$ `2Na``+``Cl_2`

`-` `Cl_2``+``H_2O` $\rightleftharpoons$ `HClO``+``HCl`

`-` `2HClO` $\xrightarrow[]{as}$ `2HCl``+``O_2↑`

`-` `MnO_2``+``4HCl``→``MnCl_2``+``Cl_2↑``+``2H_2O`

`e)`

`-` `CaO``+``H_2O``→``Ca(OH)_2`

`-` `Ca(OH)_2``+``Cl_2``→``CaOCl_2``+``H_2O`

`-` `CaOCl_2``+``2HCl``→``CaCl_2``+``Cl_2↑``+``H_2O`

`-` `CaCl_2` $\xrightarrow[]{đpnc}$ `Ca``+``Cl_2↑` 

`-` `Cl_2``+``2NaBr``+``2NaCl``+``Br_2`

`-` `Br_2``+``2NaI``→``2NaBr``+``I_2`