Đáp án:

\(\begin{array}{l}
1.{p_1} = 1,6atm\\
2.\frac{{{V_2}}}{{{V_1}}} = \frac{8}{9}
\end{array}\)

Giải thích các bước giải:

\(\begin{array}{l}
1.\\
{V_2} = {V_1} - 20\% {V_1} = 0,8{V_1}\\
{T_2} = {T_1} + 10\% {T_1} = 1,1{T_1}\\
\frac{{{p_1}{V_1}}}{{{T_1}}} = \frac{{{p_2}{V_2}}}{{{T_2}}}\\
\frac{{{p_1}{V_1}}}{{{T_1}}} = \frac{{({p_1} + 0,6)0,8{V_1}}}{{1,1{T_1}}}\\
 \Rightarrow {p_1} = ({p_1} + 0,6)\frac{8}{{11}}\\
 \Rightarrow {p_1} = 1,6atm\\
2.\\
{p_2} = {p_1} + 20\% {p_1} = 1,2{p_1}\\
{T_1} = 27 + 273 = 300^\circ K\\
{T_2} = 47 + 273 = 320^\circ K\\
\frac{{{p_1}{V_1}}}{{{T_1}}} = \frac{{{p_2}{V_2}}}{{{T_2}}}\\
 \Rightarrow \frac{{{V_2}}}{{{V_1}}} = \frac{{{p_1}{T_2}}}{{{p_2}{T_1}}} = \frac{{320{p_1}}}{{1,2{p_1}.300}} = \frac{8}{9}
\end{array}\)