Đáp án:

`↓`

Giải thích các bước giải:

`1. 2Ca + O_2` $\xrightarrow{t^o}$ `2CaO`

`2. S + O_2` $\xrightarrow{t^o}$ `SO_2`

`3. 4P + 5O_2` $\xrightarrow{t^o}$ `2P_2 O_5`

`4. 3Fe + 2O_2` $\xrightarrow{t^o}$ `Fe_3 O_4`

`5. 4Al + 3O_2` $\xrightarrow{t^o}$ `2Al_2 O_3`

`6. CH_4 + 2O_2` $\xrightarrow{t^o}$ `CO_2↑ + 2H_2 O`

`7. 2C_3 H_6 + 9O_2` $\xrightarrow{t^o}$ `6CO_2↑ + 6H_2 O`

`8. 2Zn + O_2` $\xrightarrow{t^o}$ `2ZnO`

`9. 2Cu + O_2` $\xrightarrow{t^o}$ `2CuO`

`10. 4Na + O_2` $\xrightarrow{t^o}$ `2Na_2 O`

`11. 4K + O_2` $\xrightarrow{t^o}$ `2K_2 O`

`12. 2Mg + O_2` $\xrightarrow{t^o}$ `2MgO`

Đáp án:

1.$2Ca_{}$+ $O_{2}$ → $2CaO_{}$ 

2.$S_{}$+ $O_{2}$-$t^{o}$ -> $SO_{2}$ 

3.$4P_{}$ +$5O_{2}$-$t^{o}$-> $2P_{2}$$O_{5}$ 

4.$3Fe_{}$+ $2O_{2}$-$t^{o}$-> $Fe_{3}$$O_{4}$ 

5.$4Al_{}$ +$3O_{2}$-$t^{o}$->$2Al_{2}$$O_{3}$ 

6.$CH_{4}$ + $2O_{2}$ -$t^{o}$->$CO_{2}$ + $2H_{2}$$O_{}$ 

7.$2C_{3}$$H_{6}$ +$9O_{2}$ -$t^{o}$->$6CO_{2}$ + $6H_{2}$$O_{}$ 

8.$2Zn_{}$+ $O_{2}$-$t^{o}$-> $2Zn_{}$$O_{}$ 

9.$2Cu_{}$+ $O_{2}$-$t^{o}$-> $2CuO_{}$ 

10. $4Na_{}$+ $O_{2}$-$t^{o}$-> $2Na_{2}$$O_{}$ 

11.$4K_{}$+$O_{2}$ -$t^{o}$->$2K_{2}$$O_{}$ 

12.$2Mg_{}$ + $O_{2}$ -$t^{o}$->$2MgO_{}$