EM THAM KHẢO: 

Đáp án: 

$R_{1}:$ ($C_{6}H_{10}O_{5}$)$_{n}$ : Tinh bột

$R_{2}:$ $C_{6}H_{12}O_{6}$ : Glucozơ

$R_{3}:$ $C_{2}H_{5}OH$ : Rượu etylic

$R_{4}:$ $C_{2}H_{4}$ : Etilen

$R_{5}:$ $CH_{3}COOH$ : Axit axetic

$R_{6}:$ $CH_{3}COOC_{2}H_{5}$ : Etyl axetat

$R_{7}:$ $C_{2}H_{5}ONa$ : Natri etoxit 

Giải thích các bước giải:

(1) : ($C_{6}H_{10}O_{5}$)$_{n}$ + $nH_{2}O$ $\xrightarrow[H_{2}SO_{4}]{t^{o}}$ $nC_{6}H_{12}O_{6}$

(2) : $C_{6}H_{12}O_{6}$ $\xrightarrow[]{lên men}$ $2C_{2}H_{5}OH + 2CO_{2}↑$

(3) : $C_{2}H_{5}OH \xrightarrow[xtH_{2}SO_{4}]{t^{o}} C_{2}H_{4}↑ + H_{2}O$

(4) : $C_{2}H_{4} + H_{2}O \xrightarrow[t^{o}]{xtH_{2}SO_{4}} C_{2}H_{5}OH$

(5) : $C_{2}H_{5}OH + O_{2} \xrightarrow[]{men giấm} CH_{3}COOH + H_{2}O$

(6) : $CH_{3}COOH + C_{2}H_{5}ONa → NaOH + CH_{3}COOC_{2}H_{5}$

(7) : $2CH_{3}COOC_{2}H_{5} + Ba(OH)_{2} → 2C_{2}H_{5}OH + (CH_{3}COO)_{2}Ba$

(8) : $2C_{2}H_{5}OH + 2Na → 2C_{2}H_{5}ONa + H_{2}↑$