\(\begin{array}{l}
2KCl{O_3} \to 2KCl + 3{O_2}\\
2{H_2}S + {O_2} \to 2S + 2{H_2}O\\
S + {O_2} \to S{O_2}\\
S{O_2} + B{r_2} + 2{H_2}O \to 2HBr + {H_2}S{O_4}\\
F{e_2}{O_3} + 3{H_2}S{O_4} \to F{e_2}{(S{O_4})_3} + 3{H_2}O\\
S + {H_2} \to {H_2}S\\
{H_2}S + 2B{r_2} + 2{H_2}O \to 4HBr + {H_2}S{O_4}\\
{H_2}S{O_4} + N{a_2}S{O_3} \to N{a_2}S{O_4} + S{O_2} + {H_2}O\\
S{O_2} + 2NaOH \to N{a_2}S{O_3} + {H_2}O\\
N{a_2}S{O_3} + 2HCl \to 2NaCl + S{O_2} + {H_2}O\\
2NaCl + 2{H_2}O \to 2NaOH + C{l_2} + {H_2}\\
C{l_2} + 2NaOH \to NaCl + NaClO + {H_2}O\\
C{l_2} + 2NaBr \to 2NaCl + B{r_2}\\
B{r_2} + 2NaI \to 2NaBr + {I_2}\\
{I_2} + {H_2} \to 2HI\\
HI + AgN{O_3} \to AgI + HN{O_3}\\
2KMn{O_4} \to {K_2}Mn{O_4} + Mn{O_2} + {O_2}\\
2KMn{O_4} + 16HCl \to 2KCl + 2MnC{l_2} + 5C{l_2} + 8{H_2}O\\
C{l_2} + 2Na \to 2NaCl\\
2NaCl + 2{H_2}O \to 2NaOH + C{l_2} + {H_2}\\
2NaCl + {H_2}S{O_4} \to N{a_2}S{O_4} + 2HCl\\
HCl + NaOH \to NaCl + {H_2}O\\
Fe + 2HCl \to FeC{l_2} + {H_2}\\
FeC{l_2} + 2AgN{O_3} \to Fe{(N{O_3})_2} + 2AgCl\\
2AgCl \to 2Ag + C{l_2}\\
C{l_2} + Ca{(OH)_2} \to CaOC{l_2} + {H_2}O
\end{array}\)

Đáp án:

Giải thích các bước giải:

(1) 2KClO3 --to--> 2KCl + 3O2

(2) H2S + $\frac{1}{2}$ O2 --to--> S + H2O

(3) O2 + S --to--> SO2

(4) SO2 + Br2 + 2H2O → 2HBr + H2SO4

(5) 3H2SO4 + Fe2O3 → Fe2(SO4)3 + 3H2O

(6) S + H2 --to--> H2S
(7) H2S + 4Br2 + 4H2O → 8HBr + H2SO4

(8) H2SO4 + Na2SO3 → Na2SO4 + SO2 + H2O

(9) SO2 + 2NaOH → Na2SO3 + H2O

(10) Na2SO3 + 2HCl → 2NaCl + SO2 + H2O

(11) 2NaCl --đpnc--> 2Na + Cl2

(12) Cl2 + 2NaOH → NaCl + NaClO + H2O

(13) Cl2 + 2KBr → 2KCl + Br2

(14) Br2 + 2KI → 2KBr + I2

(15) I2 + H2 --to,xt--> 2HI

(17) HI + AgNO3 → AgI + HNO3

(18) 2KMnO4 --to--> K2MnO4 + MnO2 + O2

(19) 2KMnO4 + 16HCl → 2KCl + 2MnCl2 + 5Cl2 + 8H2O

(20) Cl2 + 2Na --to--> 2NaCl

(21) 2NaCl --đpnc--> 2Na + Cl2

(22) NaCl + H2SO4 --to--> NaHSO4 + HCl

(23) NaOH + HCl → NaCl + H2O

(24) 2HCl + Fe → FeCl2 + H2

(25) FeCl2 + 2AgNO3 → 2AgCl + Fe(NO3)2

(26) AgCl --ánh sáng--> Ag + $\frac{1}{2}$ Cl2

(23) Cl2 + Ca(OH)2 --to--> CaOCl2 + H2O