Đáp án:

 1) C3H8O

2) 0,625M

3) 72% và 28%

Giải thích các bước giải:

\(\begin{array}{l}
1)\\
CTHH:{C_x}{H_y}{O_z}\\
\% O = 100 - 60 - 13,33 = 26,67\% \\
x:y:z = \dfrac{{60}}{{12}}:\dfrac{{13,33}}{1}:\dfrac{{26,67}}{{16}} = 3:8:1\\
 =  > CTDGN:{C_3}{H_8}O\\
MX = 60g/mol\\
X:{({C_3}{H_8}O)_n}\\
 \Rightarrow 60n = 60 \Rightarrow n = 1\\
CTPT:{C_3}{H_8}O\\
2)\\
Fe + 2HCl \to FeC{l_2} + {H_2}\\
n{H_2} = \dfrac{{5,6}}{{22,4}} = 0,25\,mol\\
nHCl = 0,25 \times 2 = 0,5\,mol\\
CMHCl = \dfrac{{0,5}}{{0,8}} = 0,625M\\
3)\\
Mg + {H_2}S{O_4} \to MgS{O_4} + {H_2}\\
n{H_2} = \dfrac{{6,72}}{{22,4}} = 0,3\,mol\\
nMg = n{H_2} = 0,3\,mol\\
mMg = 0,3 \times 24 = 7,2g\\
mCu = 10 - 7,2 = 2,8g\\
\% mMg = \dfrac{{7,2}}{{10}} \times 100\%  = 72\% \\
\% mCu = 100 - 72 = 28\% 
\end{array}\)