Đáp án:

 a) 4,4g

b) 50% và 50%

c) 0,5625

Giải thích các bước giải:

\(\begin{array}{l}
a)\\
Fe + S \to FeS\\
nFe = \dfrac{{5,6}}{{56}} = 0,1\,mol\\
nS = \dfrac{{1,6}}{{32}} = 0,05\,mol\\
\dfrac{{0,1}}{1} > \dfrac{{0,05}}{1}\\
 =  > nFeS = nS = 0,05\,mol\\
mFeS = 0,05 \times 88 = 4,4g\\
b)\\
nFe\,spu = 0,1 - 0,05 = 0,05\,mol\\
Fe + 2HCl \to FeC{l_2} + {H_2}\\
0,05\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0,05\\
FeS + 2HCl \to FeC{l_2} + {H_2}S\\
0,05\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0,05\\
\% V{H_2} = \% V{H_2}S = 50\% \\
c)\\
Mhh = \dfrac{{0,05 \times 34 + 0,05 \times 2}}{{0,1}} = 18\\
dhh/{O_2} = \dfrac{{18}}{{32}} = 0,5625
\end{array}\)