Đáp án:

 1/

$Etanol:C_{2}H_{5}OH$

$2C_{2}H_{5}OH \buildrel{{H_{2}SO_{4}đ,140^oC }}\over\longrightarrow C_{2}H_{5}OC_{2}H_{5}+H_{2}O$

2/

+$Etanol:C_{2}H_{5}OH$

+$Metanol:CH_{3}OH$

$CH_{3}OH +CH_{2}H_{5}OH \buildrel{{H_{2}SO_{4}đ,140^oC }}\over\longrightarrow C_{2}H_{5}OCH_{3}+H_{2}O$

3/

$propan-1-ol:CH_{2}OH-CH_{2}-CH_{3}$

$C_{2}OH-CH_{2}-CH_{3} \buildrel{{H_{2}SO_{4}đ,170^oC }}\over\longrightarrow  CH_{2}=CH-CH_{3} +H_{2}O$

4/

$propan-2-ol:CH_{3}-CHOH-CH_{3}$

 $CH_{3}-CHOH-CH_{3} \buildrel{{H_{2}SO_{4}đ,170^oC }}\over\longrightarrow  CH_{2}=CH-CH_{3}+H_{2}O$

5/

$butan-1-ol:CH_{2}OH-CH_{2}-CH_{2}-CH_{3}$

$CH_{2}OH-CH_{2}-CH_{2}-CH_{3} \buildrel{{H_{2}SO_{4}đ,170^oC }}\over\longrightarrow  CH_{3}=CH-CH_{2}-CH_{3}+H_{2}O$

6/

$butan-2-ol:CH_{3}-CHOH-CH_{2}-CH_{3}$

$CH_{3}-CHOH-CH_{2}-CH_{3} \buildrel{{H_{2}SO_{4}đ,170^oC }}\over\longrightarrow      CH_{2}=CH-CH_{2}-CH_{3}+H_{2}O(\text{Sản phẩm phụ})$

$CH_{3}-CHOH-CH_{2}-CH_{3} \buildrel{{H_{2}SO_{4}đ,170^oC }}\over\longrightarrow               CH_{3}-CH=CH-CH_{3}+H_{2}O(\text{Sản phẩm  chính})$

7/

$2-metylbutan-2-ol:(CH_{3})_{2}-C(OH)-CH_{2}-CH_{3}$

$(CH_{3})_{2}-C(OH)-CH_{2}-CH_{3} \buildrel{{H_{2}SO_{4}đ,170^oC }}\over\longrightarrow      CH_{3}-C(CH_{3})=CH-CH_{3}+H_{2}O (\text{Sản phẩm chính})$

$(CH_{3})_{2}-C(OH)-CH_{2}-CH_{3} \buildrel{{H_{2}SO_{4}đ,170^oC }}\over\longrightarrow       CH_{2}=C(CH_{3})-CH-CH_{3}+H_{2}O (\text{Sản phẩm phụ})$

Đáp án:

Giải thích các bước giải:

1. 2C2H5OH --H2SO4,140 đô--> C2H5-O-C2H5 + H2O

2.  C2H5OH + CH3OH --H2SO4,140 đô--> C2H5OCH3 + H2O

3. CH3-CH2-CH2-OH --to,H2SO4--> CH2=CH-CH3 + H2O

4. CH3-CH(OH)-CH3 --to,H2SO4--> CH2=CH-CH3 + H2O

5. CH3-CH2-CH2-CH2-OH --to,H2SO4--> CH3-CH2-CH=CH2 + H2O

6. CH3-CH(OH)-CH2-CH3 --to,H2SO4--> CH3-CH=CH-CH3 + H2O

                                                                     (sản phẩm chính)

7. CH3-C(OH)(CH3)-CH2-CH3 --to,H2SO4--> CH3-C(CH3)=CH-CH3 +H2O

                                                                             (Sản phẩm chính)