Đáp án:

\(\begin{array}{l}
a.1,{6.10^{ - 6}}\left( {{\rm{W}}b} \right)\\
b.1,{6.10^{ - 3}}\left( V \right)\\
{8.10^{ - 5}}\left( H \right)
\end{array}\)

Giải thích các bước giải:

\[\begin{array}{l}
a.B = 4\pi {.10^{ - 7}}\frac{N}{l}I = 4\pi {.10^{ - 7}}.\frac{{100}}{{0,314}}.2 = {8.10^{ - 4}}\left( T \right)\\
{\Phi _1} = Bs\cos \alpha  = {8.10^{ - 4}}{.20.10^{ - 4}}\cos {0^0} = 1,{6.10^{ - 6}}\left( {{\rm{W}}b} \right)\\
b.\left| e \right| = \left| {\frac{{\Delta \Phi }}{{\Delta t}}} \right| = \left| {\frac{{N{\Phi _1} - 0}}{{\Delta t}}} \right| = \left| {\frac{{100.1,{{6.10}^{ - 6}}}}{{0,1}}} \right| = 1,{6.10^{ - 3}}\left( V \right)\\
\left| e \right| = L\left| {\frac{{\Delta I}}{{\Delta t}}} \right|\\
 \Rightarrow 1,{6.10^{ - 3}} = L.\frac{2}{{0,1}}\\
 \Rightarrow L = {8.10^{ - 5}}\left( H \right)
\end{array}\]