Đáp án:

Giải thích các bước giải:

$1/$

$a,4Al+3O_2\buildrel{{t^o}}\over\longrightarrow$ $2Al_2O_3$

$2Zn+O_2\buildrel{{t^o}}\over\longrightarrow$ $2ZnO$

$3Fe+2O_2\buildrel{{t^o}}\over\longrightarrow$ $Fe_3O_4$

$2Cu+O_2\buildrel{{t^o}}\over\longrightarrow$ $2CuO$

$4Na+O_2\buildrel{{t^o}}\over\longrightarrow$ $2Na_2O$

$C+O_2\buildrel{{t^o}}\over\longrightarrow$ $CO_2$

$S+O_2\buildrel{{t^o}}\over\longrightarrow$ $SO_2$

$4P+5O_2\buildrel{{t^o}}\over\longrightarrow$ $2P_2O_5$

$b,2CO+O_2\buildrel{{t^o}}\over\longrightarrow$ $2CO_2$

$CH_4+2O_2\buildrel{{t^o}}\over\longrightarrow$ $CO_2+2H_2O$

$2C_2H_2+5O_2\buildrel{{t^o}}\over\longrightarrow$ $4CO_2+2H_2O$

$C_2H_6O+3O_2\buildrel{{t^o}}\over\longrightarrow$ $2CO_2+3H_2O$

$2/$

$n_{O_2}=\frac{33,6}{22,4}=1,5mol.$

$a,PTPƯ:C+O_2\buildrel{{t^o}}\over\longrightarrow$ $CO_2$

$Theo$ $pt:$ $n_{CO_2}=n_{O_2}=1,5mol.$

$⇒m_{C}=1,5.12=18g.$

$b,PTPƯ:2H_2+O_2\buildrel{{t^o}}\over\longrightarrow$ $2H_2O$

$Theo$ $pt:$ $n_{H_2}=2n_{O_2}=3mol.$

$⇒m_{H_2}=3.2=6g.$

$c,PTPƯ:S+O_2\buildrel{{t^o}}\over\longrightarrow$ $SO_2$

$Theo$ $pt:$ $n_{S}=n_{O_2}=1,5mol.$

$⇒m_{S}=1,5.32=48g.$

$d,PTPƯ:4P+5O_2\buildrel{{t^o}}\over\longrightarrow$ $2P_2O_5$

$Theo$ $pt:$ $n_{P}=\frac{4}{5}n_{O_2}=\frac{4}{5}.1,5=1,2mol.$

$⇒m_{P}=1,2.31=37,2g.$

$3/$

$PTPƯ:$

$CH_4+2O_2\buildrel{{t^o}}\over\longrightarrow$ $CO_2+2H_2O$

$2C_2H_2+5O_2\buildrel{{t^o}}\over\longrightarrow$ $4CO_2+2H_2O$

$C_2H_6O+3O_2\buildrel{{t^o}}\over\longrightarrow$ $2CO_2+3H_2O$

chúc bạn học tốt!

Đáp án:

Giải thích các bước giải:

 Bài 1

a) 4Al +3O2-->2Al2O3

2Zn+O2-->2ZnO

3Fe +2O2-->FE3O4

2Cu+O2-->2CuO

4Na+O2--->2Na2O

C+O2-->CO2

S+O2-->SO2

4P+5O2-->2P2O5

b) 2CO+O2-->2CO2

CH4+2O2--->CO2+2H2O

C2H2+5/2O2-->2CO2+H2O

C2H6O+3O2-->2CO2+3H2O

Bài 2

n O2=33,6/22,4=1,5(mol)

a)C+O2-->CO2

n C=n O2=1,5(mol)

m C=1,5.12=18(g)

b) 2H2+O2--->2H2O

n H2=2n O2=3(mol)

m H2=3.2=6(g)

c) 4P+5O2-->2P2O5

n P=4/5 n O2=1,2(mol)

m P=1,2.31=37,2(g)

bài 3

CH4+2O2---to-->CO2+2H2O

C2H2+5/2O2---to--->2CO2+H2O

C2H6O+3O2-->2CO2+3H2O