Đáp án:

Giải thích các bước giải:

$1/$

$a,C+O_2\buildrel{{t^o}}\over\longrightarrow$ $CO_2$

$S+O_2\buildrel{{t^o}}\over\longrightarrow$ $SO_2$

$4P+5O_2\buildrel{{t^o}}\over\longrightarrow$ $2P_2O_5$

$2Zn+O_2\buildrel{{t^o}}\over\longrightarrow$ $2ZnO$

$4Al+3O_2\buildrel{{t^o}}\over\longrightarrow$ $2Al_2O_3$

$3Fe+2O_2\buildrel{{t^o}}\over\longrightarrow$ $Fe_3O_4$

$2Cu+O_2\buildrel{{t^o}}\over\longrightarrow$ $2CuO$

$CH_4+2O_2\buildrel{{t^o}}\over\longrightarrow$ $CO_2+H_2O$

$C_2H_6O+3O_2\buildrel{{t^o}}\over\longrightarrow$ $2CO_2+3H_2O$

$b,2KClO_3\buildrel{{đp}}\over\longrightarrow$ $2KCl+3O_2$

$2KMnO_4\buildrel{{đp}}\over\longrightarrow$ $K_2MnO_4+MnO_2+O_2$

$2/$

$a,PTPƯ:4Al+3O_2\buildrel{{t^o}}\over\longrightarrow$ $2Al_2O_3$

$b,n_{Al}=\frac{10,8}{27}=0,4mol.$

$Theo$ $pt:$ $n_{O_2}=\frac{3}{4}n_{Al}=0,3mol.$

$⇒V_{O_2}=0,3.22,4=6,72l.$

$c,Theo$ $pt:$ $n_{Al_2O_3}=\frac{1}{2}n_{Al}=0,2mol.$

$⇒m_{Al_2O_3}=0,2.102=20,4g.$

$3/$

$PTPƯ:2KClO_3\buildrel{{đp}}\over\longrightarrow$ $2KCl+3O_2$

$n_{KClO_3}=\frac{49}{122,5}=0,4mol.$

$Theo$ $pt:$ $n_{O_2}=\frac{3}{2}n_{KMnO_4}=0,6mol.$

$⇒V_{O_2}=0,6.22,4=13,44l.$

$4/$

$CO_2→H_2CO_3$

$P_2O_5→H_3PO_4$

$SO_3→H_2SO_4$

$N_2O_5→HNO_3$

$SiO_2→H_2SiO_3$

$SO_2→H_2SO_3$

$Na_2O→NaOH$

$K_2O→KOH$

$BaO→Ba(OH)_2$

$Al_2O_3→Al(OH)_3$

$Fe_2O_3→Fe(OH)_3$

$FeO→Fe(OH)_2$

chúc bạn học tốt!

1)

a) 

C+O2->CO2

S+O2->SO2

4P+5O2->2P2O5

2Zn+O2->2ZnO

4Al+3O2->2Al2O3

4Fe+3O2->2Fe2O3

2Cu+O2->2CuO

CH4+3O2->CO2+2H2O

C2H6O+3O2->2CO2+3H2O

b)

2KClO3->2KCl+3O2

2KMnO4->MnO2+O2+K2MnO4

2)

a)PT: 4Al+3O2->2Al2O3

b)Ta có: nAl=10,8/27=0,4(mol)

=>nO2=3/4x0,4=0,3(mol)

=>VO2=0,3x22,4=6,72(lít)

c)Ta có:

nAl2O3=2/4x0,4=0,2(mol)

=>mAl2O3=0,2x(27x2+16x3)=20,4(g)

3) PT:2KClO3->2KCl+3O2

nKClO3=49:(19+35,5+16x3)=0,4(mol)

=>nO2=3/2x0,4=0,6(mol)

=>VO2=0,6x22,4=13,44(lít)

4)

CO2 : H2CO3

P2O5 : H3PO4

SO3 : H2SO4

N2O5 : HNO3

SiO2 : H2SiO3

SO2 : H2SO3

Na2O : NaOH

K2O : KOH

BaO : Ba(OH)2

Al2O3 : Al(OH)3

Fe2O3 : Fe(OH)3

FeO : Fe(OH)2