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Bài `2`:

`a)` $\frac{-6}{11}$+$\frac{5}{11}$=`-1`

`b)` $\frac{-5}{16}$+$\frac{-3}{16}$<$\frac{1}{3}$

`c)` $\frac{2}{5}$<$\frac{3}{4}$+$\frac{-1}{6}$

`d)` $\frac{5}{6}$+$\frac{-2}{3}$>$\frac{1}{12}$+$\frac{-4}{5}$

Bài `3`:

`a)` `x`=$\frac{1}{3}$+$\frac{-2}{5}$

⇒ `x`=$\frac{5}{15}$+$\frac{-6}{15}$

⇒`x`=$\frac{-1}{15}$

Vậy `x`=$\frac{-1}{15}$.

`b)` `x`=$\frac{1}{5}$+$\frac{2}{11}$

⇒`x`=$\frac{11}{55}$+$\frac{10}{55}$

⇒`x`=$\frac{21}{55}$

Vậy `x`=$\frac{21}{55}$.

`c)` $\frac{x}{15}$=$\frac{3}{5}$+$\frac{-2}{5}$

⇒$\frac{x}{15}$=$\frac{9}{15}$+$\frac{-10}{15}$

⇒$\frac{x}{15}$=$\frac{=1}{15}$

⇒`x`=`-1`

Vậy `x`=`-1`.

`d)` $\frac{11}{18}$+$\frac{13}{6}$=$\frac{85}{x}$

⇒$\frac{33}{24}$+$\frac{52}{24}$=$\frac{85}{x}$

⇒$\frac{85}{24}$=$\frac{85}{x}$

⇒`x`=`24`

Vậy `x`=`24`.

Đáp án:

Bài 2
$a)\frac{-6}{11}+\frac{5}{-11}=-1\\
b)\frac{-5}{16}+\frac{-3}{16}=\frac{-1}{2}<\frac{-1}{3}\\
c) \frac{3}{4}+\frac{-1}{6}>\frac{2}{5}\\
d)  \frac{5}{6}+\frac{-2}{3}> \frac{1}{12}+\frac{-4}{5}$
Bài 3
$ a)x=\frac{-1}{15}\\
b) x=\frac{21}{55}\\
c)  x=-1\\
d) x=24$

Giải thích các bước giải:

Bài 2
$a)\frac{-6}{11}+\frac{5}{-11}=-1=-1\\
b)\frac{-5}{16}+\frac{-3}{16}=\frac{-1}{2}<\frac{-1}{3}\\
c) \frac{3}{4}+\frac{-1}{6}=\frac{7}{12}>\frac{7}{14}=\frac{1}{2}=\frac{2}{4}>\frac{2}{5}\\
d) \frac{5}{6}+\frac{-2}{3}=\frac{1}{6}\\
\frac{1}{12}+\frac{-4}{5}=\frac{-43}{60}\\
\Rightarrow \frac{-43}{60}<\frac{1}{6}\Rightarrow \frac{5}{6}+\frac{-2}{3}> \frac{1}{12}+\frac{-4}{5}$
Bài 3
$ a)x=\frac{1}{3}+\frac{-2}{5}=\frac{5}{15}-\frac{6}{15}=\frac{-1}{15}\\
b) x=\frac{1}{5}+\frac{2}{11}=\frac{11}{55}+\frac{10}{55}=\frac{21}{55}\\
c) \frac{x}{15}=\frac{3}{5}+\frac{-2}{3}=\frac{9}{15}+\frac{-10}{15}=\frac{-1}{15}\Rightarrow x=-1\\
d) \frac{11}{8}+\frac{13}{6}=\frac{85}{x}\\
\Leftrightarrow \frac{33}{24}+\frac{52}{24}=\frac{85}{x}\\
\Leftrightarrow \frac{85}{24}=\frac{85}{x}\\
\Leftrightarrow x=24$