Xin hay nhất ạaa,lâu xĩu luôn

$\text{Đáp án+Giải thích các bước giải:}$

$\text{1) 3Fe+$2O_{2}$→$Fe_{3}O_{4}$}$

$\text{2) 4K+$O_{2}$→$2K_{2}O$}$

$\text{3) S+$O_{2}$→$SO_{2}$}$

$\text{4) $P_{2}O_{5}$+$3H_{2}O$→$2H_{3}PO_{4}$}$

$\text{5) 2Mg+$O_{2}$→2MgO}$

$\text{6) $N_{2}O_{5}$+$H_{2}O$→$2H_{3}NO_{3}$}$

$\text{7) $Cu(OH)_{2}$→CuO+$H_{2}O$}$

$\text{8) $Fe(OH)_{2}$→FeO+$H_{2}O$}$

$\text{9) $CaCO_{3}$→CaO+$CO_{2}$}$

$\text{10) $2KClO_{3}$→2KCl+$3O_{2}$}$

$\text{11) $2KMnO_{4}$→$K_{2}MnO_{4}$+$MnO_{2}$+$O_{2}$}$

$\text{12) $2Fe(OH)_{3}$→$Fe_{2}O_{3}$+$3H_{2}O$}$

$\text{13) $2NaNO_{3}$→$2NaNO_{2}$+$O_{2}$}$

$\text{14) 2Al+$3FeSO_{4}$→$Al_{2}(SO_{4})_{3}$+3Fe}$

$\text{15) 2K+$2H_{2}O$→2KOH+$H_{2}$}$

$\text{16) 2Na+$2H_{2}O$→2NaOH+$H_{2}$}$

$\text{17) Ca+$2H_{2}O$→$Ca(OH)_{2}$+$H_{2}$}$

$\text{18) Ba+$2H_{2}O$→$a(OH)_{2}$+$H_{2}$}$

$\text{19) Mg+$2AgNO_{3}$→$Mg(NO_{3})_{2}$+2Ag}$

$\text{20) 2Al+$3CuCl_{2}$→$2AlCl_{3}$+3Cu}$

$\text{21) 2Al+$3H_{2}SO_{4}$→$Al_{2}(SO_{4})_{3}$+$3H_{2}$}$

$\text{22) Zn+2HCl→$ZnCl_{2}$+$H_{2}$}$

$\text{23) Fe+2HCl→$FeCl_{2}$+$H_{2}$}$

$\text{24) 2Al+$2H_{3}PO_{4}$→$2AlPO_{4}$+$3H_{2}$}$

$\text{25) $Fe_{2}O_{3}$+6HCl→$2FeCl_{3}$+$3H_{2}O$}$

$\text{26) CuO+2HCl→$CuCl_{2}$+$H_{2}O$}$

$\text{27) 2Fe+$3Cl_{2}$→$2FeCl_{3}$}$

$\text{28) 4Cr+$3O_{2}$→$2Cr_{2}O_{3}$}$

$\text{29) 2Fe+$3Br_{2}$→$2FeBr_{3}$}$

$\text{30) $2H_{2}$+$O_{2}$→$2H_{2}O$}$

$\text{31) $2C_{2}H_{2}$+$5O_{2}$→$4CO_{2}$+$2H_{2}O$}$

$\text{32) $C_{2}H_{4}$+$3O_{2}$→$2CO_{2}$+$2H_{2}O$}$

$\text{33) $CH_{4}$+$2O_{2}$→$CO_{2}$+$2H_{2}O$}$

$\text{34) $BaCl_{2}$+$2AgNO_{3}$→2AgCl+$Ba(NO_{3})_{2}$}$

$\text{35) 6NaOH+$Fe_{2}(SO_{4})_{3}$→$2Fe(OH)_{3}$+$3Na_{2}SO_{4}$}$

$\text{36) $Na_{2}CO_{3}$+$Ca(OH)2$→$CaCO_{3}$+2NaOH}$

$\text{37) 2HCl+$CaCO_{3}$→$CaCl_{2}$+$CO_{2}$+$H_{2}O$}$

$\text{38) $CuCl_{2}$+$2AgNO_{3}$→2AgCl+$(NO_{3})_{2}$}$

$\text{39) $Na_{2}SO_{4}$+$BaCl_{2}$→2NaCl+$BaSO_{4}$}$

$\text{40) $H_{2}$+CuO→Cu+$H_{2}O$}$

$\text{41) $3H_{2}$+$Fe_{2}O_{3}$→2Fe+$3H_{2}O$}$

$\text{42) $H_{2}$+FeO→Fe+$H_{2}O$}$

$\text{43) $4H_{2}$+$Fe_{3}O_{4}$→3Fe+$4H_{2}O$}$

$\text{44) $H_{2}$+PbO→+$H_{2}O$}$

$\text{45) 2Al+3CuO→$Al_{2}O_{3}$+3Cu}$

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